Belt Length

[Unforgiven]

helping a friend out putting a 16 HP Briggs vany in a 2000 txt. What is the best way to measure for the new belt? Oil filter is keeping us from sliding the motor to the rear.

[Firefytr29wfd]

Measure around the inner sheave of the drive clutch, and around the outside of the driven and add 2". Read that a few places on the forums and that is what I did to get the belt for mine.

[Unforgiven]

thanks

[Unforgiven]

well neighbor and good friend bought a 2000 txt with 4 inch lift and a half running 295 cc
valves where shot.

He had a used 16 hp Briggs Vanguard that he got in a trade(freebie) I told him that it would work in the Ezgo.

I fabbed him an engine craddle and we used my old clutch until he can get the cpp adapter. We used some 1" EMT prebents to build a header. A used belt from a sweeper truck. Add in a few hours work and he has a Big Block Ezgo. I think he has about $10 in bolts and wires.

Belt was a little short. We got a measurement on the belt length (47") I figured he will have $100 in the swap,......not to mention he got a heck of a deal on the cart.

[fstg21]

The equation for determining belt length is:

L= ((2*a*D2+2*a*D1)*Pi+D2^2-2*D1*D2+D1^2+8*a^2)/(4*a)

a=the center to center distance (distance between the center of the bolt holding on the drive and the bolt holding on the driven.)

Pi= if you don't know what this is, where in trouble.

D1=The Diameter of the drive clutch with the belt wrapped around it. Measure with a cheap dial caliper.(the belt is important because all belts are measured by the outside circumference not the inside)

D2= The diameter of the Driven Clutch with the belt wrapped around it. An easy way to measure this is to take it off the cart lay it on the concrete and mark it's diameter (with the belt on it) with a pencil then measure the distance between the marks with a tape.

So assuming I can do math(questionable)

Lets do a hypothetical:

(These aren't real numbers, so your mileage may vary.)

a= 14"

D1= 2"

D2= 9"

((2*14*9+2*14*2)*PI+9^2-2*2*9+2^2+8*14^2)/(4*14)= 46.15 (assuming no slack)

252+56*PI= 967.61

81-36+4+1568=1617

967.61+1617=2584.61

2584.61/56= 46.15"

If that makes sense.

To figure out the amount of slack you want
You use right angle triangle Theorem.
In this same example scenario:

B = the opposite leg of the triangle

a = our center to center distance still.

C = the length of the belt between the pulleys

S = the amount of slack you want

Y = is one half of the extra length needed + (C/2)

X = the extra belt length needed for the slack you want.

(D2/2)-(D1/2)=B

4.5-1=3.5

a^2+B^2=C^2

14^2 + 3.5^2= 208.25 sqrt of 208.25 is 14.43 14.43=C

Then to set slack:

(C/2)^2+S^2=Y^2

(14.43/2)^2+1^2= 53.06 sqrt53.06=7.284 Y=7.284

2Y-C=X

2(7.284)-14.43=.138

X+L=Total Belt Length Needed .138+46.15= 46.288

It only takes a .138" longer belt to add 1" of slack over a 14" center to center.

If I hadn't done the math I wouldn't have believed it.

[fastercarter]

Originally Posted by fstg21

The equation for determining belt length is:

L= ((2*a*D2+2*a*D1)*Pi+D2^2-2*D1*D2+D1^2+8*a^2)/(4*a)

a=the center to center distance (distance between the center of the bolt holding on the drive and the bolt holding on the driven.)

Pi= if you don't know what this is, where in trouble.

D1=The Diameter of the drive clutch with the belt wrapped around it. Measure with a cheap dial caliper.(the belt is important because all belts are measured by the outside circumference not the inside)

D2= The diameter of the Driven Clutch with the belt wrapped around it. An easy way to measure this is to take it off the cart lay it on the concrete and mark it's diameter (with the belt on it) with a pencil then measure the distance between the marks with a tape.

So assuming I can do math(questionable)

Lets do a hypothetical:

(These aren't real numbers, so your mileage may vary.)

a= 14"

D1= 2"

D2= 9"

((2*14*9+2*14*2)*PI+9^2-2*2*9+2^2+8*14^2)/(4*14)= 46.15 (assuming no slack)

252+56*PI= 967.61

81-36+4+1568=1617

967.61+1617=2584.61

2584.61/56= 46.15"

If that makes sense.

To figure out the amount of slack you want
You use right angle triangle Theorem.
In this same example scenario:

B = the opposite leg of the triangle

a = our center to center distance still.

C = the length of the belt between the pulleys

S = the amount of slack you want

Y = is one half of the extra length needed + (C/2)

X = the extra belt length needed for the slack you want.

(D2/2)-(D1/2)=B

4.5-1=3.5

a^2+B^2=C^2

14^2 + 3.5^2= 208.25 sqrt of 208.25 is 14.43 14.43=C

Then to set slack:

(C/2)^2+S^2=Y^2

(14.43/2)^2+1^2= 53.06 sqrt53.06=7.284 Y=7.284

2Y-C=X

2(7.284)-14.43=.138

X+L=Total Belt Length Needed .138+46.15= 46.288

It only takes a .138" longer belt to add 1" of slack over a 14" center to center.

If I hadn't done the math I wouldn't have believed it.

I never was much use at math

FC

[fstg21]

Swap the letters for your numbers then copy and paste into the google search bar and it will be done.

[rifter]

Hummm,,,,my head hurts.

[pachanga90]

They make 3 different Oil-Filter housings with different mounting angles for the filter.One of these should help you get more clearance.

[Unforgiven]

It's in and hauls butt. It just is going to take a 47 1/2 inch belt.