Can someone explain reducer 'amps' to me?

[yurtle]

Yep.

Volts = pressure.
Amps = flowrate.
Higher pressure (voltage) requires thicker pipe (insulation).
Bigger pipe (cables) allows more flowrate (amps).

[Steve390Gold]

Originally Posted by hyper1

Yea I was trying to explain it as simple to enable someone to get the idea without all the technical stuff. You are correct so here is how it works.

A neat analogy to help understand these terms is a system of plumbing pipes. The voltage is equivalent to the water pressure, the current is equivalent to the flow rate, and the resistance is like the pipe size.
There is a basic equation in electrical engineering that states how the three terms relate. It says that the current is equal to the voltage divided by the resistance or I = V/R. This is known as Ohm's law.
Let's see how this relation applies to the plumbing system. Let's say you have a tank of pressurized water connected to a hose that you are using to water the garden.
What happens if you increase the pressure in the tank? You probably can guess that this makes more water come out of the hose. The same is true of an electrical system: Increasing the voltage will make more current flow.
Let's say you increase the diameter of the hose and all of the fittings to the tank. You probably guessed that this also makes more water come out of the hose. This is like decreasing the resistance in an electrical system, which increases the current flow.
Electrical power is measured in watts. In an electrical system power (P) is equal to the voltage multiplied by the current.
The water analogy still applies. Take a hose and point it at a waterwheel like the ones that were used to turn grinding stones in watermills. You can increase the power generated by the waterwheel in two ways. If you increase the pressure of the water coming out of the hose, it hits the waterwheel with a lot more force and the wheel turns faster, generating more power. If you increase the flow rate, the waterwheel turns faster because of the weight of the extra water hitting it.
A neat analogy to help understand these terms is a system of plumbing pipes. The voltage is equivalent to the water pressure, the current is equivalent to the flow rate, and the resistance is like the pipe size.
There is a basic equation in electrical engineering that states how the three terms relate. It says that the current is equal to the voltage divided by the resistance or I = V/R. This is known as Ohm's law.
Let's see how this relation applies to the plumbing system. Let's say you have a tank of pressurized water connected to a hose that you are using to water the garden.
What happens if you increase the pressure in the tank? You probably can guess that this makes more water come out of the hose. The same is true of an electrical system: Increasing the voltage will make more current flow.
Let's say you increase the diameter of the hose and all of the fittings to the tank. You probably guessed that this also makes more water come out of the hose. This is like decreasing the resistance in an electrical system, which increases the current flow.
Electrical power is measured in watts. In an electrical system power (P) is equal to the voltage multiplied by the current.
The water analogy still applies. Take a hose and point it at a waterwheel like the ones that were used to turn grinding stones in watermills. You can increase the power generated by the waterwheel in two ways. If you increase the pressure of the water coming out of the hose, it hits the waterwheel with a lot more force and the wheel turns faster, generating more power. If you increase the flow rate, the waterwheel turns faster because of the weight of the extra water hitting it.
In an electrical system, increasing either the current or the voltage will result in higher power. Let's say you have a system with a 6-volt light bulb hooked up to a 6-volt battery. The power output of the light bulb is 100 watts. Using the equation I = P/V, we can calculate how much current in amps would be required to get 100 watts out of this 6-volt bulb.
You know that P = 100 W, and V = 6 V. So, you can rearrange the equation to solve for I and substitute in the numbers.
In an electrical system, increasing either the current or the voltage will result in higher power. Let's say you have a system with a 6-volt light bulb hooked up to a 6-volt battery. The power output of the light bulb is 100 watts. Using the equation I = P/V, we can calculate how much current in amps would be required to get 100 watts out of this 6-volt bulb.
You know that P = 100 W, and V = 6 V. So, you can rearrange the equation to solve for I and substitute in the numbers.
I = 100 W/6 V = 16.67 amps
What would happen if you use a 12-volt battery and a 12-volt light bulb to get 100 watts of power?
I = 100 W/12 V = 8.33 amps
So, this latter system produces the same power, but with half the current. There is an advantage that comes from using less current to make the same amount of power. The resistance in electrical wires consumes power, and the power consumed increases as the current going through the wires increases. You can see how this happens by doing a little rearranging of the two equations. What you need is an equation for power in terms of resistance and current. Let's rearrange the first equation:
I = V/R can be restated as V = I*R
Now you can substitute the equation for V into the other equation:
P = V*I substituting for V we get P = I*R*I, or P = I2*R
What this equation tells you is that the power consumed by the wires increases if the resistance of the wires increases (for instance, if the wires get smaller or are made of a less conductive material). But it increases dramatically if the current going through the wires increases. So, using a higher voltage to reduce the current can make electrical systems more efficient. The efficiency of electric motors also improves at higher voltages.
This improvement in efficiency is what drove the automobile industry to consider switching from 12-volt electrical systems to 42-volt systems in the 1990s. As more cars shipped with electric-powered amenities — video displays, seat heaters, "smart" climate control — they required thick bundles of wiring to supply enough current. Switching to a higher-voltage system would provide more power with thinner-gauge wiring.
The switch never happened, because carmakers were able to boost efficiencies with digital technology and more efficient electric pumps at 12 volts. But some new models employ hybrid systems with a separate 48-volt generator to power advanced features like idle shut-off while increasing overall system efficiency.

Lets not forget that P=IV and V=IR are very gross estimations and that in an inductive load the current leads the voltage by a good bit so the two values are not quite in phase with each other. This results in most of your lost efficiency and why PIV/VIR equations dont exactly play out in field testing.

For some real fun try measuring amplifier output at a specific frequency using a DMM and clamp meter and the actual wattage you are putting into a speaker vs the rated amount you amp produces will boggle your mind. BackEMF is such a little monster....lol if and when you do such a measurement, it is also fun to work out a resistance vs frequency played curve. Your subs, youll find will never actually drop down to their static resistance measurements unless you play a frequency below the tuning of the box.

[hyper1]

Originally Posted by bubba4dad

Funny how googling Amps can make you and electrical engineer....lol

https://science.howstuffworks.com/en...uestion501.htm

Yea like most on here, google is always your friend.

[Lateparker]

What reducer did you end up going with?

[Dela]

Originally Posted by Lateparker

What reducer did you end up going with?

Got this - just installed last night. Buzzing sound instantly gone

30 Amp Golf Cart Voltage Reducer

Wired to fuse block - going to run speaker bar, subwoofer, lights, tv, undercarriage lights off of it. Hope it can handle all of them

threw the new key switch in as well - more to come on this long weekend

[orangeman6]

What sub is that?

[cgtech]

Lol, I love the battery cable routing. I bet the battery caps never come off that way (even for battery maintenance).

[hyper1]

Originally Posted by cgtech

Lol, I love the battery cable routing. I bet the battery caps never come off that way (even for battery maintenance).

that is the most sercure battery cap hold down

[TexTurbo]

Re the cable routing....

I can see that helping secure them down during "re-entry"......

[Dela]

Originally Posted by cgtech

Lol, I love the battery cable routing. I bet the battery caps never come off that way (even for battery maintenance).

CG - exactly why I routed them that way - I haul *** around the course and the caps come loose every so often - not no more